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0.25x^2=36
We move all terms to the left:
0.25x^2-(36)=0
a = 0.25; b = 0; c = -36;
Δ = b2-4ac
Δ = 02-4·0.25·(-36)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6}{2*0.25}=\frac{-6}{0.5} =-12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6}{2*0.25}=\frac{6}{0.5} =12 $
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